iOS开发 子视图中获取父控制器、父视图

Objective-C

/**
获取父控制器

@param view 当前视图
@param className 需要获取的控制器名称
@return 返回控制器对象
*/
- (UIViewController *)LCZGetSuperViewController:(UIView *)currentview superViewControllerClassName:(NSString *)className
{
    for (UIView* next = [current superview]; next; next = next.superview) {
        UIResponder *nextResponder = [next nextResponder];
        if ([nextResponder isKindOfClass:[NSClassFromString(className) class]]) {
            return (UIViewController *)nextResponder;
        }
    }
    return nil;
}

/**
获取当前视图中的目标父视图

@param currentView 当前视图
@param superView 父视图
@return 父视图对象
*/
- (UIView *)LCZGetSuperView:(UIView *)currentView superView:(UIView *)superView {
    UIView *view = currentView.superview;
    while (![view isKindOfClass:[superView class]]) {
        if (view.superview == nil) {
            return nil;
        } else {
            view = [view superview];
        }
    }
    return view;
}

Swift

/// 通过当前视图获取父视图的控制器
///
/// - Parameters:
///   - currentView: 当前视图
///   - viewController: 需要获取到的控制器
/// - Returns: 返回控制器
func LCZGetSuperViewController<T: UIViewController>(currentView:UIView, viewController: T.Type) -> T? {
    var view: UIView = currentView.superview!
    while view.next!.isKind(of: T.self) != true {
        guard view.superview != nil else {
            return nil
        }
        view = view.superview!
    }
    return view.next as? T
}

/// 获取当前视图中的目标父视图
///
/// - Parameters:
///   - currentView: 当前视图
///   - superView: 目标父视图
/// - Returns: 返回父视图
public func LCZGetSuperView<T: UIView>(currentView: UIView, superView: T.Type) -> T? {
    var view: UIView = currentView.superview!
    while view.isKind(of: T.self) != true {
        guard view.superview != nil else {
            return nil
        }
        view = view.superview!
    }
    return view as? T
}